How do you factor completely $40xy^2 − 36x^2y$ ?

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Answer 1 · 2016-05-13T20:51:22

$40xy^2-36x^2y = 4xy(10y-9x)$

Note that both of the terms are divisible by $4$ , $x$ and $y$ , so therefore by $4xy$ .

Separate this out as a factor:

$40xy^2-36x^2y = 4xy(10y-9x)$

How do you factor completely 40xy^2 − 36x^2y40xy^2 − 36x^2y?