How do you factor completely $4 a x + 3 a y + 4 b x + 3 b y$ $4ax+3ay+4bx+3by$ ?

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How do you factor completely $4 a x + 3 a y + 4 b x + 3 b y$ $4ax+3ay+4bx+3by$ ?

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Answer 1 · 2015-12-29T00:08:33

Factor by grouping to find:

$4 a x + 3 a y + 4 b x + 3 b y = (a + b) (4 x + 3 y)$ $4ax+3ay+4bx+3by = (a+b)(4x+3y)$

Explanation:

$4 a x + 3 a y + 4 b x + 3 b y$ $4ax+3ay+4bx+3by$

$= (4 a x + 3 a y) + (4 b x + 3 b y)$ $=(4ax+3ay)+(4bx+3by)$

$= a (4 x + 3 y) + b (4 x + 3 y)$ $=a(4x+3y)+b(4x+3y)$

$= (a + b) (4 x + 3 y)$ $= (a+b)(4x+3y)$

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How do you factor completely $4 a x + 3 a y + 4 b x + 3 b y$ $4ax+3ay+4bx+3by$ ?

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How do you factor completely $4 a x + 3 a y + 4 b x + 3 b y$ $4ax+3ay+4bx+3by$ ?