How do you factor completely 4ax + 8ay + 3bx + 6by 4ax+8ay+3bx+6by?

1 Answer
George C.
Nov 19, 2015

Factor by grouping to find:

4ax+8ay+3bx+6by=(4a+3b)(x+2y)4ax+8ay+3bx+6by=(4a+3b)(x+2y)

Explanation:

Notice that the first two terms are both divisible by 4a4a and the last two terms are both divisible by 3b3b, so try factoring by grouping:

4ax+8ay+3bx+6by4ax+8ay+3bx+6by

=(4ax+8ay)+(3bx+6by)=(4ax+8ay)+(3bx+6by)

=4a(x+2y)+3b(x+2y)=4a(x+2y)+3b(x+2y)

=(4a+3b)(x+2y)=(4a+3b)(x+2y)

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