How do you factor completely: $-4y^2 + 12y - 16$ ?

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Answer 1 · 2015-07-29T00:34:27

Factor: f(y) = -4y^2 + 12y - 16

f(y) = -4(y^2 - 3y + 4)
The trinomial in the parentheses can't be factored because its determinant D = b^2 - 4ac = 9 - 16 = -7 < 0

How do you factor completely: -4y^2 + 12y - 16-4y^2 + 12y - 16?