How do you factor completely $8bc^2+24bc$ ?

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Answer 1 · 2018-04-30T00:26:07

$8bc(c+3)$

A GCF can be factored out from both of them: $8bc$

Use the distributive property: $8bc(c+3)$

$c+3$ cannot be factored out anymore

How do you factor completely 8bc^2+24bc8bc^2+24bc?