How do you factor completely $a^{2} + 2 a c - a b - b c + c^{2}$ $a^2 + 2ac - ab - bc + c^2$ ?

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How do you factor completely $a^{2} + 2 a c - a b - b c + c^{2}$ $a^2 + 2ac - ab - bc + c^2$ ?

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Answer 1 · 2016-08-28T19:45:31

$a^{2} + 2 a c - a b - b c + c^{2} = (a + c - b) (a + c)$ $a^2+2ac-ab-bc+c^2=(a+c-b)(a+c)$

Explanation:

$a^{2} + 2 a c - a b - b c + c^{2}$ $a^2+2ac-ab-bc+c^2$

$= (a^{2} + 2 a c + c^{2}) - (a b + b c)$ $=(a^2+2ac+c^2)-(ab+bc)$

$= {(a + c)}^{2} - b (a + c)$ $=(a+c)^2-b(a+c)$

$= ((a + c) - b) (a + c)$ $=((a+c)-b)(a+c)$

$= (a + c - b) (a + c)$ $=(a+c-b)(a+c)$

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How do you factor completely $a^{2} + 2 a c - a b - b c + c^{2}$ $a^2 + 2ac - ab - bc + c^2$ ?

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Explanation:

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How do you factor completely a^2 + 2ac - ab - bc + c^2a2+2ac−ab−bc+c2a^2 + 2ac - ab - bc + c^2?

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How do you factor completely $a^{2} + 2 a c - a b - b c + c^{2}$ $a^2 + 2ac - ab - bc + c^2$ ?