How do you factor completely a^2 - 4b^2 - 4a + 4?

1 Answer
Sep 2, 2016

a^2-4b^2-4a+4 = (a-2b-2)(a+2b-2)

Explanation:

The difference of squares identity can be written:

A^2-B^2 = (A-B)(A+B)

We use this with A=(a-2) and B=2b as follows:

a^2-4b^2-4a+4 = (a^2-4a+4)-4b^2

color(white)(a^2-4b^2-4a+4) = (a-2)^2-(2b)^2

color(white)(a^2-4b^2-4a+4) = ((a-2)-2b)((a-2)+2b)

color(white)(a^2-4b^2-4a+4) = (a-2b-2)(a+2b-2)