How do you factor completely $x^(2/3)+5x^(1/3)-36$ ?

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Answer 1 · 2016-04-19T23:39:36

I got: $(root3(x)+9)(root3(x)-4)$

We can try writing the fractional exponent as a root:
$root3(x^2)+5root3(x)-36$
set $root3(x)=s$
we get:
$s^2+5s-36=(s+9)(s-4)$

or: $(root3(x)+9)(root3(x)-4)$

How do you factor completely x^(2/3)+5x^(1/3)-36x^(2/3)+5x^(1/3)-36?