How do you factor completely x^3+64x3+64?
1 Answer
May 11, 2016
Explanation:
Both
So we can use the sum of cubes identity:
a^3+b^3 = (a+b)(a^2-ab+b^2)a3+b3=(a+b)(a2−ab+b2)
with
x^3+64x3+64
=x^3+4^3=x3+43
=(x+4)(x^2-x(4)+4^2)=(x+4)(x2−x(4)+42)
=(x+4)(x^2-4x+16)=(x+4)(x2−4x+16)