How do you factor completely x3−9x? Algebra Polynomials and Factoring Factoring Completely 1 Answer Shwetank Mauria Aug 1, 2016 x3−9x=x(x+3)(x−3) Explanation: x3−9x = x(x2−9) = x(x2−32) Now using identity a2−b2=(a+b)(a−b), we get x(x2−32) = x(x+3)(x−3) Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x2−8? Which method do you use to factor 3x(x−1)+4(x−1)? What are the factors of 12x3+12x2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor 12c2−75 completely? How do you factor x6−26x3−27? How do you factor 100x2+180x+81? See all questions in Factoring Completely Impact of this question 20484 views around the world You can reuse this answer Creative Commons License