How do you factor completely $z^{2} + 36 z + 324$ $z^2 + 36z + 324$ ?

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Answer 1 · 2016-08-29T08:57:50

$z^{2} + 36 z + 324 = z^{2} + 2 (18 z) + 18^{2} = {(z + 18)}^{2}$ $z^2+36z+324 = z^2+2(18z)+18^2 = (z+18)^2$

This is a perfect square trinomial: $18^{2} = 324$ $18^2=324$ and $36 = 2 \cdot 18$ $36=2*18$ , so we find:

$z^{2} + 36 z + 324 = z^{2} + 2 (18 z) + 18^{2} = {(z + 18)}^{2}$ $z^2+36z+324 = z^2+2(18z)+18^2 = (z+18)^2$

How do you factor completely z^2 + 36z + 324z2+36z+324z^2 + 36z + 324?