How do you factor $m^{2} - 10 m + 24$ $m^2 - 10m + 24$ ?

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Answer 1 · 2015-10-11T19:12:39

Look for numbers that you can x to get 24 and add to get -10.

$- 6$ $-6$ and $- 4$ $-4$ would seem to fit the bill:

$(m - 6) (m - 4)$ $(m-6)(m-4)$

Check by multiplying out $\Rightarrow$ $rArr$

$m^{2} - 4 m - 6 m + 24$ $m^2-4m-6m+24$

$= m^{2} - 10 m + 24$ $=m^2-10m+24$

Which is good.

Answer 2 · 2015-10-11T19:13:23

$m^{2} - 10 m + 24 = (m - 4) (m - 6)$ $m^2-10m+24=(m-4)(m-6)$

$m^{2} - 10 m + 24$ $m^2-10m+24$

Determine what two numbers add up to $- 10$ $-10$ and multiply to $24$ $24$ .

The numbers $- 4$ $-4$ and $- 6$ $-6$ meet the criteria.

$m^{2} - 10 m + 24 = (m - 4) (m - 6)$ $m^2-10m+24=(m-4)(m-6)$

How do you factor m^2 - 10m + 24m2−10m+24m^2 - 10m + 24?