How do you factor $n^{2} - n - 56$ $n^2-n-56$ ?

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Answer 1 · 2015-05-28T21:00:23

Notice $8 \times 7 = 56$ $8 xx 7 = 56$ and $8 - 7 = 1$ $8 - 7 = 1$

So

$n^{2} - n - 56 = n^{2} - (8 - 7) n - (8 \times 7)$ $n^2-n-56 = n^2-(8-7)n-(8xx7)$

$= (n - 8) (n + 7)$ $=(n-8)(n+7)$

How do you factor n^2-n-56n2−n−56n^2-n-56?