How do you factor $(n+4)^2 - y^2$ ?

Question

I see that this is a difference of two squares, but how do I continue factoring it after I get to $((n+4)+y)((n+4)-y)$ ?
Or, is this as far as it can be factored?

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Answer 1 · 2017-11-11T13:02:31

$(n+y+4)(n-y+4)$

Given $(n+4)^2 - y^2$

Let $x = n + 4$

$:. = x^2 - y^2$

$= (x+y)(x-y)$

Substituting for value of x,

$= (n + 4 +y)(n + 4 -y)$