How do you factor $(pi)r^2 - 4(pi)r+4(pi)$ ?

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Answer 1 · 2016-10-02T18:40:13

= $pir^2$

Before you factor, you will see that there are two terms which are additive inverses. We end up with one term!

$pi r^2 -4pir +4pir$

= $pir^2$

If you factor anyway - take out a common factor of $pir$

= $pir(r +4-4)$

= $pir(r)$

= $pir^2$

How do you factor (pi)r^2 - 4(pi)r+4(pi) (pi)r^2 - 4(pi)r+4(pi) ?