How do you factor $r^{2} + 12 r + 27$ $r^2+12r+27$ ?

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Answer 1 · 2015-11-07T13:02:39

$r^{2} + 12 r + 27 = (r + 9) (r + 3)$ $r^2+12r+27 = (r+9)(r+3)$

Find a pair of factors of $27$ $27$ whose sum is $12$ $12$ :

$9 \times 3 = 27$ $9 xx 3 = 27$ works, so:

$r^{2} + 12 r + 27 = (r + 9) (r + 3)$ $r^2+12r+27 = (r+9)(r+3)$

How do you factor r2+12r+27r^2+12r+27 ?