How do you factor $sin^2(x) + sin x - 2$ ?

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Answer 1 · 2016-04-22T04:06:51

We have that

$sin^2(x) + sin x - 2=sin^2x+sinx-1-1= (sin^ 2x-1)+(sinx-1)=(sinx-1)*(sinx+1)+(sinx-1)= (sinx-1)*(sinx+2)$

How do you factor sin^2(x) + sin x - 2 sin^2(x) + sin x - 2 ?