How do you factor the expression $12s^2 + 6s - 6$ ?

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Answer 1 · 2016-07-20T05:33:39

$12s^2+6s-6=6(s+1)(2s-1)$

To factorize a quadratic polynomial such as $ax^2+bx+c=0$ , one can spit middle term $b$ in two parts whose product is $a×c$ .

Hence, in $12s^2+6s-6$ , one needs to split $+6$ in two parts so that their product is $12×(-6)=-72$ and these are $-6$ and $12$ .

Hence $12s^2+6s-6$

= $12s^2-6s+12s-6$

= $6s(2s-1)+6(2s-1)$

= $(6s+6)(2s-1)$

= $6(s+1)(2s-1)$

How do you factor the expression 12s^2 + 6s - 612s^2 + 6s - 6?