How do you factor the expression 12x² - 21x + 3?

1 Answer
Gerardina C.
Jun 9, 2016

12(x-(7+sqrt(33))/8)(x-(7-sqrt(33))/8)

Explanation:

First let's factor
3(4x^2-7x+1)
Then find the zeroes for
4x^2-7x+1
x=(7+-sqrt(7^2-4*4*1))/(2*4)
x=(7+-sqrt(33))/8
then we can factor again:

3*4(x-(7+sqrt(33))/8)(x-(7-sqrt(33))/8)
or
12(x-(7+sqrt(33))/8)(x-(7-sqrt(33))/8)

Related questions
See all questions in Factorization of Quadratic Expressions
Impact of this question
1246 views around the world
You can reuse this answer
Creative Commons License