How do you factor the expression 133 + 208y + 64y^2?

1 Answer
Shwetank Mauria
Mar 3, 2016

(7+8y)(19+8y)

Explanation:

To factorize the expression 133+208y+64y^2, one needs to multiply the coefficient of degree two of y i.e.64 and independent term 133, which gives us 8512.

Now find two factors of 8512, whose product is 8512 and sum is the coefficient of x i.e. 208. These would be 56 and 152. Splitting middle term accordingly, we get

133+208y+64y^2

= 133+56y+152y+64y^2

= 7(19+8y)+8y(19+8y)

= (7+8y)(19+8y)

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