How do you factor the expression $18 r^{2} + 12 r y - 3 x r - 2 x y$ $18r^2 + 12ry - 3xr - 2xy$ ?

Question

How do you factor the expression $18 r^{2} + 12 r y - 3 x r - 2 x y$ $18r^2 + 12ry - 3xr - 2xy$ ?

1 Answer

Impact of this question

1699 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-05T15:38:58

(3r + 2y)(6r - x)

Explanation:

group the terms into 2 'pairs'

hence: [ $18 r^{2} + 12 r y] + [- 3 x r - 2 x y]$ $18r^2 + 12ry ] + [ -3xr - 2xy ]$

now factor each pair:

6r(3r + 2y) - x(3r + 2y)

There is a common factor of (3r + 2y) in each pair.

thus : (3r + 2y )(6r - x)

Science

Math

Humanities

... and beyond

How do you factor the expression $18 r^{2} + 12 r y - 3 x r - 2 x y$ $18r^2 + 12ry - 3xr - 2xy$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor the expression 18r2+12ry−3xr−2xy18r^2 + 12ry - 3xr - 2xy?

1 Answer

Explanation:

Related questions

Impact of this question

How do you factor the expression $18 r^{2} + 12 r y - 3 x r - 2 x y$ $18r^2 + 12ry - 3xr - 2xy$ ?