How do you factor the expression -2a^2-ab+3b^2−2a2−ab+3b2?

1 Answer
iceman
Mar 24, 2016

-(a-b)(2a+3b)−(a−b)(2a+3b)

Explanation:

−2a^2−ab+3b^2−2a2−ab+3b2 => Factor out -1:
=-(2a^2+ab-3b^2)=−(2a2+ab−3b2)
Write the 2nd term as factors of 1st and last term i.e:
ab=-2ab+3abab=−2ab+3ab => We get:
=-(2a^2-2ab+3ab-3b^2)=−(2a2−2ab+3ab−3b2) => Factor by grouping:
=-[2a(a-b)+3b(a-b)]=−[2a(a−b)+3b(a−b)] => Finally:
=-(a-b)(2a+3b)=−(a−b)(2a+3b)

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