How do you factor the expression $2 x^{2} - 9 x - 5$ $2x^2-9x-5$ ?

Question

How do you factor the expression $2 x^{2} - 9 x - 5$ $2x^2-9x-5$ ?

1 Answer

Impact of this question

1456 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-12T09:19:24

$(2 x + 1) (x - 5)$ $(2x+1)(x-5)$

Explanation:

$using the a-c method to factorise the quadratic$ $"using the a-c method to factorise the quadratic"$

$the factors of the product 2 \times - 5 = - 10$ $"the factors of the product "2xx-5=-10$

$which sum to - 9 are - 10 and + 1$ $"which sum to - 9 are - 10 and + 1"$

$split the middle term using these factors$ $"split the middle term using these factors"$

$2 x^{2} - 10 x + x - 5 \leftarrow factor by grouping$ $2x^2-10x+x-5larrcolor(blue)"factor by grouping"$

$= 2 x (x - 5) + 1 (x - 5)$ $=color(red)(2x)(x-5)color(red)(+1)(x-5)$

$take out the common factor (x - 5)$ $"take out the "color(blue)"common factor "(x-5)$

$= (x - 5) (2 x + 1)$ $=(x-5)(color(red)(2x+1))$

$\Rightarrow 2 x^{2} - 9 x - 5 = (x - 5) (2 x + 1)$ $rArr2x^2-9x-5=(x-5)(2x+1)$

Science

Math

Humanities

... and beyond

How do you factor the expression $2 x^{2} - 9 x - 5$ $2x^2-9x-5$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor the expression 2x^2-9x-52x2−9x−52x^2-9x-5?

1 Answer

Explanation:

Related questions

Impact of this question

How do you factor the expression $2 x^{2} - 9 x - 5$ $2x^2-9x-5$ ?