How do you factor the expression $3x^2 + 10x - 8$ ?

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Answer 1 · 2016-03-05T17:02:52

$(3x-2) (x+4)$ is the factorised form of the expression.

$3x^2 +10x-8$

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like $ax^2 + bx + c$ , we need to think of 2 numbers such that:

$N_1*N_2 = a*c = 3*-8 = -24$

AND

$N_1 +N_2 = b = 10$

After trying out a few numbers we get $N_1 = 12$ and $N_2 =-2$

$12*-2 = -24$ , and $12+(-2)= 10$

$3x^2 +10x-8 =3x^2 +12x -2x-8$

$= 3x (x+4) -2 (x+4)$

$= (3x-2) (x+4)$

$(3x-2) (x+4)$ is the factorised form of the expression.

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