How do you factor the expression $5 x^{2} + 8 x - 21$ $5x^2+8x-21$ ?

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How do you factor the expression $5 x^{2} + 8 x - 21$ $5x^2+8x-21$ ?

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Answer 1 · 2016-03-12T22:48:34

$\Rightarrow (x + 3) 5 x - 7)$ $=>(x+3)5x-7)$

Explanation:

$5 \times 21 = 5 \times 3 \times 7 = 15 \times 7$ $5xx21=5xx3xx7=15xx7$
15-7=8
$5 x^{2} + 8 x - 21$ $5x^2+8x-21$
$\Rightarrow 5 x^{2} + 15 x - 7 x - 21$ $=>5x^2+15x-7x-21$
$\Rightarrow 5 x (x + 3) - 7 (x + 3)$ $=>5x(x+3)-7(x+3)$
$\Rightarrow (x + 3) 5 x - 7)$ $=>(x+3)5x-7)$

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How do you factor the expression $5 x^{2} + 8 x - 21$ $5x^2+8x-21$ ?

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