How do you factor the expression $5x^2-8x+3$ ?

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Answer 1 · 2018-04-04T15:47:52

you have to expand the middle term in such a way that their addition is equal to the middle term and multiplication is equal to 5*3(in this case)

$5x^2-8x+3=0$
$5x^2-5x-3x+3=0$
$5x(x-1)-3(x-1)=0$
$(5x-3)(x-1)=0$
hence(5x-3)(x-1)are the factors

How do you factor the expression 5x^2-8x+35x^2-8x+3?