How do you factor the expression $7 (x - y) - z (x - y)$ $7(x-y)-z(x-y)$ ?

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Answer 1 · 2016-07-23T12:20:34

$(x - y) (7 - z)$ $(x-y)(7-z)$

This is exactly the same as factoring $7 a - z a$ $7a - za$ where there is a common factor of $a$ $a$ , leading to $a (7 - z)$ $a(7 - z)$

However, in this case, instead of a single variable as the common factor, there is an entire bracket which appears in both terms.

$7 (x - y) - z (x - y)$ $7color(blue)((x-y))-zcolor(blue)((x-y))$

Divide each term by the common bracket

$(x - y) (7 - z)$ $color(blue)((x-y))(7-z)$

How do you factor the expression 7(x-y)-z(x-y)7(x−y)−z(x−y)7(x-y)-z(x-y)?