How do you factor the expression $81 x^{\frac{4}{5}} - 256$ $81x^(4/5) - 256$ ?

Question

1715 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-02T15:18:38

$(9 x^{\frac{2}{5}} - 16) \cdot (9 x^{\frac{2}{5}} + 16)$ $(9x^(2/5)-16)*(9x^(2/5)+16)$

$(\sqrt{81 x^{\frac{4}{5}}} - \sqrt{256}) \cdot (\sqrt{81 x^{\frac{4}{5}}} + \sqrt{256})$ $(sqrt(81x^(4/5))-sqrt(256))*(sqrt(81x^(4/5))+sqrt(256))$

$\sqrt{81 x^{\frac{4}{5}}} = 9 x^{\frac{2}{5}}$ $color(green)(sqrt(81x^(4/5))=9x^(2/5)$

$\sqrt{256} = 16$ $color(green)(sqrt(256)=16$

$(9 x^{\frac{2}{5}} - 16) \cdot (9 x^{\frac{2}{5}} + 16)$ $(9x^(2/5)-16)*(9x^(2/5)+16)$

How do you factor the expression 81x^(4/5) - 25681x45−256 81x^(4/5) - 256?