How do you factor the expression $9 x^{3} + 18 x^{2} + 7 x + 14$ $9x^3 + 18x^2 + 7x + 14$ ?

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How do you factor the expression $9 x^{3} + 18 x^{2} + 7 x + 14$ $9x^3 + 18x^2 + 7x + 14$ ?

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Answer 1 · 2016-03-08T20:22:43

$(x + 2) (9 x^{2} + 7)$ $(x +2)(9x^2 + 7)$

Explanation:

'split' the expression into two groups

so [ $9 x^{3} + 18 x^{2}] + [7 x + 14]$ $9x^3 + 18x^2 ] + [ 7x + 14 ]$

now factorise each group

$9 x^{3} + 18 x^{2} = 9 x^{2} (x + 2) and 7 x + 14 = 7 (x + 2)$ $9x^3+18x^2 = 9x^2(x+2) " and " 7x+14= 7(x+2)$

there is now a common factor of (x+2) in each pair

$\Rightarrow 9 x^{3} + 18 x^{2} + 7 x + 14 = (x + 2) (9 x^{2} + 7)$ $rArr 9x^3+18x^2+7x+14 = (x+2)(9x^2+7)$

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How do you factor the expression $9 x^{3} + 18 x^{2} + 7 x + 14$ $9x^3 + 18x^2 + 7x + 14$ ?

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Explanation:

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How do you factor the expression $9 x^{3} + 18 x^{2} + 7 x + 14$ $9x^3 + 18x^2 + 7x + 14$ ?