How do you factor the expression #b^3 - 6b^2 - 27b#?

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Answer 1 · 2018-07-15T02:52:38

#b(b-9)(b+3)#

#b^3-6b^2-27b#

=#b(b^2-6b-27)#

#b=(6+-sqrt(36+108))/2#

#b=(6+-sqrt144)/2#

#b=(6+-12)/2#

#b=(6+12)/2=9# or #b=(6-12)/2=-3#

=#b(b-9)(b-(-3))#

=#b(b-9)(b+3)#