How do you factor the expression $b^3 - 6b^2 - 27b$ ?

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Answer 1 · 2018-07-15T02:52:38

$b(b-9)(b+3)$

$b^3-6b^2-27b$

= $b(b^2-6b-27)$

$b=(6+-sqrt(36+108))/2$

$b=(6+-sqrt144)/2$

$b=(6+-12)/2$

$b=(6+12)/2=9$ or $b=(6-12)/2=-3$

= $b(b-9)(b-(-3))$

= $b(b-9)(b+3)$

How do you factor the expression b^3 - 6b^2 - 27bb^3 - 6b^2 - 27b?