How do you factor the expression $w^3-3w^2-54w$ ?

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Answer 1 · 2018-03-19T00:14:00

$w^3-3w^2-54w = w(w-9)(w+6)$

Given:

$w^3-3w^2-54w$

Note that all of the terms are divisible by $w$ , so we can separate that out as a factor. Then note that $54 = 9 * 6$ and $9 - 6 = 3$ , so we find:

$w^3-3w^2-54w = w(w^2-3w-54) = w(w-9)(w+6)$

How do you factor the expression w^3-3w^2-54w w^3-3w^2-54w ?