How do you factor the expression $x^{2} + 14 x + 48$ $x^2+14x+48$ ?

Question

27499 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-22T08:21:15

$(x + 6) (x + 8)$ $(x+6)(x+8)$

$x^{2} + 14 x + 48$ $x^2+14x+48$

we have two brackets like

$(x +_) (x +_)$ $( x + color(white)(_ ))(x +color(white)( _) )$

the blank spaces will be numbers such that they are factors of the constant $48$ $48$ that add up to the coefficient of $x$ $x$ that is $14$ $14$

we have $6 & 8$ $6" & "8$

$x^{2} + 14 x + 48 = (x + 6) (x + 8)$ $x^2+14x+48=(x+6)(x+8)$

How do you factor the expression x2+14x+48x^2+14x+48?