How do you factor the expression $x^2 - 2x - 8$ ?

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Answer 1 · 2018-05-06T18:55:01

$(x-4)(x+2)$

$"since the coefficient of "x^2" term is 1 then"$

$"the factors of - 8 which sum to - 2 are - 4 and + 2"$

$rArrx^2-2x-8=(x-4)(x+2)$

How do you factor the expression x^2 - 2x - 8x^2 - 2x - 8?