How do you factor the expression $x^{2} + 9 x + 8$ $x^2 + 9x + 8$ ?

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Answer 1 · 2018-04-30T21:22:33

$\Rightarrow (x + 1) (x + 8)$ $=>(x+1)(x+8)$

$\Rightarrow x^{2} + 9 x + 8$ $=>x^2+9x+8$

We need to find two factors of $8$ $8$ , such that the sum of the two factors is $9$ $9$ .

Factors of $8$ $8$ :

$\Rightarrow 1, 8 \to 1 + 8 = 9$ $=>1,8 -> 1+8=9$
$\Rightarrow 2, 4 \to 2 + 4 = 6$ $=>2,4 -> 2+4=6$

As we can see, the factors $1$ $1$ and $8$ $8$ give us a sum of $9$ $9$ .

Hence,

$\Rightarrow x^{2} + 9 x + 8 = (x + 1) (x + 8)$ $=>x^2+9x+8=(x+1)(x+8)$

How do you factor the expression x^2 + 9x + 8x2+9x+8x^2 + 9x + 8?