How do you factor the expression $y^2 + 14xy + 49x^2$ ?

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Answer 1 · 2016-04-10T12:35:05

$y^2+14xy+49x^2=(y+7x)(y+7x)=(y+7x)^2$

This is a perfect square trinomial

$a^2+2ab+b^2=(a+b)(a+b)$

with $a=y$ and $b=7x$

$y^2+14xy+49x^2=(y+7x)(y+7x)=(y+7x)^2$

God bless....I hope the explanation is useful.

How do you factor the expression y^2 + 14xy + 49x^2y^2 + 14xy + 49x^2?