How do you factor the expressions $112a^2b - 343b$ ?

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Answer 1 · 2016-04-06T21:05:37

$112a^2b-343b= 7b(4a-7)(4a+7)$

First note that both terms are divisible by $7b$ , so separate that out as a factor first. Then use the difference of squares identity:

$A^2-B^2 = (A-B)(A+B)$

with $A=4a$ and $b=7$ as follows:

$112a^2b-343b$

$= 7b(16a^2-49)$

$= 7b((4a)^2-7^2)$

$= 7b(4a-7)(4a+7)$

How do you factor the expressions 112a^2b - 343b 112a^2b - 343b ?