How do you factor the expressions $3x^2+4x+1$ ?

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Answer 1 · 2016-03-03T11:03:37

$(3x+1)(x+1)$

3 is a prime number so it can only be a product of $1xx3$

1 cab only be a product of $1xx1$

So we have $" "(3x+1)(x+1) = 3x^2+3x+x+1$

This works so the answer is:

$(3x+1)(x+1)$

How do you factor the expressions 3x^2+4x+13x^2+4x+1?