How do you factor the expressions $c^{3} - 5 c^{2} - 14 c$ $c^3-5c^2-14c$ ?

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Answer 1 · 2018-03-04T12:45:02

c (c-7) (c+2)

take out the factor c
therefore,
c( $c^{2} - 5 c - 14$ $c^2-5c-14$ )
then use St.Andrews cross method,
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