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How do you factor the expressions $x^{2} - 16 x + 63 = 0$ $x^2 - 16x + 63 = 0$ ?

1 Answer

Apr 23, 2016

$(x - 7) (x - 9) = 0$ $(x-7)(x-9) = 0$

Explanation:

In general:

$(x - a) (x - b) = x^{2} - (a + b) + a b$ $(x-a)(x-b) = x^2-(a+b)+ab$

We find $63 = 7 \times 9$ $63 = 7 xx 9$ and $16 = 7 + 9$ $16 = 7 + 9$ , so:

$x^{2} - 16 x + 63 = (x - 7) (x - 9)$ $x^2-16x+63 = (x-7)(x-9)$

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