How do you factor the trinomial $1-14x+49x^2$ ?

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Answer 1 · 2018-03-05T04:31:23

$1 - 14x + 49x^2 = (1 - 7x)(1 - 7x) = (1 - 7x)^2 = (7x - 1)^2$

Answer 2 · 2018-03-05T05:15:48

$(x-7)(x-7)$

$1-14x+49x^2$

The information you need to find the factors is contained in the terms of this quadratic trinomial:

there are $3$ terms in ascending powers of $x$
the factors will be $(x???)(x???)$
we need to find factors of $49$ which ADD to make $14$
(the sign of $49$ is positive $rarr$ ADD)
$7xx7 = 49 and 7 +7 = 14$
The factors will be $(x?7)(x?7)$

The positive sign of $49$ indicates that the signs in the brackets must be the SAME becasue $+xx+ = + and -xx- = +$

The sign of the middle term $-14x$ indicates that the signs will be negative.

$(x-7)(x-7)$

How do you factor the trinomial 1-14x+49x^21-14x+49x^2?