How do you factor the trinomial $10x^2-9x+6$ ?

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Answer 1 · 2016-01-23T22:12:49

Not factorable

D = b^2 - 4ac = 81 - 240 < 0. Since D is not a perfect square, this trinomial can't be factored.

How do you factor the trinomial 10x^2-9x+610x^2-9x+6?