How do you factor the trinomial $12 y^2- 17y +5$ ?

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Answer 1 · 2018-03-07T09:33:52

$(12y-5)(y-1)$

$12y^2-17y+5$

multiply the coeff of $y^2" & the constant"$

$12xx5=60$

find factors of $60" that add to "-17$

$-12,-5$

start by reducing the $y$ term with these factors then factorise by grouping.

$12y^2-12y-5y+5$

$(12y^2-12y)-(5y-5)$

$12y(y-1)-5(y-1)$

$(12y-5)(y-1)$

How do you factor the trinomial 12 y^2- 17y +512 y^2- 17y +5?