How do you factor the trinomial $12x^2-6x-18$ ?

Question

1595 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-24T13:33:57

$6(2x-3)(x+1)$

Frist take out any common factors.

$12x^2 - 6x -18 = 6(2x^2 - x - 3)$

The factors of $2$ are $2$ and $1$ , and the factors of $3$ are $3$ and $1$ .

The expression is therefore $6(2x-3)(x+1)$

How do you factor the trinomial 12x^2-6x-1812x^2-6x-18?