Question

How do you factor the trinomial `14x^2 – 19x – 3`?

Answer 1

`14x^2-19x-3=(7x+1)(2x-3)`

Explanation:

To factorize `14x^2-19x-3`, we should split the coefficient of middle term `-19` in two parts whose product is product of coefficients of other two terms, i.e. `14xx(-3)=-42`.

The pair could be `+2` and `-21` and hence

`14x^2-19x-3`

= `14x^2-21x+2x-3`

= `7x(2x-3)+1(2x-3)`

= `(7x+1)(2x-3)`