How do you factor the trinomial $16x^3 − 24x^2 + 8x$ ?

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Answer 1 · 2015-12-18T00:09:37

Separate out the common factor of the terms, then factor by grouping to find:

$16x^3-24x^2+8x=8x(2x-1)(x-1)$

Separate out the common factor $8x$ of the terms, then split the middle term of the remaining quadratic and factor by grouping:

$16x^3-24x^2+8x$

$=8x(2x^2-3x+1)$

$=8x(2x^2-2x-x+1)$

$=8x((2x^2-2x)-(x-1))$

$=8x(2x(x-1)-1(x-1))$

$=8x(2x-1)(x-1)$

How do you factor the trinomial 16x^3 − 24x^2 + 8x16x^3 − 24x^2 + 8x?