How do you factor the trinomial $2 x^{2} + 4 x - 198$ $2x^2 + 4x - 198$ ?

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How do you factor the trinomial $2 x^{2} + 4 x - 198$ $2x^2 + 4x - 198$ ?

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Answer 1 · 2016-03-30T04:34:52

y = 2(x - 9)(x + 11)

Explanation:

$y = 2 (x^{2} + 2 x - 99)$ $y = 2(x^2 + 2x - 99)$
Find 2 numbers knowing sum (b = 2) and product (c = -99).
Factor pairs of (-99) --> (-9, 11). This sum is 2 = b. Then these 2 numbers are -9 and 11.
$y = 2 (x - 9) (x + 11)$ $y = 2(x - 9)(x + 11)$

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How do you factor the trinomial $2 x^{2} + 4 x - 198$ $2x^2 + 4x - 198$ ?

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How do you factor the trinomial $2 x^{2} + 4 x - 198$ $2x^2 + 4x - 198$ ?