How do you factor the trinomial $3r ^3 -3r ^2-6r$ ?

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Answer 1 · 2016-03-01T04:11:59

$3r^3-3r^2-6r=color(blue)(3r(r+1)(r-2))$

$3r^3-3r^2-6r$

Factor out the GCF $3r$ .

$3r(r^2-r-2)$

Factor $r^2-r-2$ .

Find two numbers that when added equal $-1$ and when multiplied equal $-2$ . The numbers $1$ and $-2$ meet the requirements.

Rewrite the expression as its factors.

$3r(r+1)(r-2)$

How do you factor the trinomial 3r ^3 -3r ^2-6r3r ^3 -3r ^2-6r?