How do you factor the trinomial $3x^2+2x-1=0$ ?

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Answer 1 · 2016-03-01T18:35:58

$(3x-1) (x+1)$ is the factorised form of the expression.

$3x^2 + 2x- 1 =0$

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like $ax^2 + bx + c$ , we need to think of 2 numbers such that:

$N_1*N_2 = a*c = 3*-1 = -3$

AND

$N_1 +N_2 = b = 2$

After trying out a few numbers we get $N_1 = -1$ and $N_2 =3$
$3*-1 = -3$ , and $3+(-1)= 2$

$3x^2 + 2x- 1 =3x^2 + 3x -1x- 1$

$= 3x(x+1) -1 (x+1)$

$= (3x-1) (x+1)$

$(3x-1) (x+1)$ is the factorised form of the expression.

How do you factor the trinomial 3x^2+2x-1=03x^2+2x-1=0?