How do you factor the trinomial $3 x^{2} + 3 x - 60 = 0$ $3x^2 + 3x - 60 = 0$ ?

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Answer 1 · 2016-05-14T11:06:26

You first take out the obvious factor $3$ $3$

$\to 3 (x^{2} + 1 \cdot x - 20) = 0$ $->3(x^2+1*x-20)=0$

We need two numbers that add up to $1$ $1$ and multiply to $- 20$ $-20$

These are $- 4 and + 5$ $-4and+5$

$\to 3 (x - 4) (x + 5) = 0$ $->3(x-4)(x+5)=0$

Solutions to the equation are $x = + 4 or x = - 5$ $x=+4orx=-5$

How do you factor the trinomial 3x^2 + 3x - 60 = 03x2+3x−60=0 3x^2 + 3x - 60 = 0?