How do you factor the trinomial $3x^2+9xy-30y^2$ ?

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Answer 1 · 2018-05-01T11:06:01

$3(x+5y)(x-2y)$

$"take out a "color(blue)"common factor "3$

$=3(x^2+3xy-10y^2)$

$"the factors of - 10 which sum to + 3 are + 5 and - 2"$

$=3(x+5y)(x-2y)$

How do you factor the trinomial 3x^2+9xy-30y^23x^2+9xy-30y^2?